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Study Guides > Mathematics for the Liberal Arts

L1.05: Section 4

Section 4: Using Solver to choose the best kind of model

Sometimes data has a pattern for which more than one kind of model is a potential match. While visual inspection of the best-fit graphs will usually show which one is best, you can also choose between candidates by seeing which model type has the smallest best-fit standard deviation.

Example 6: Does a quadratic model fit the population data better than the model in Example 3? Why?

Solution approach: [a] Use Solver with the Quadratic Model worksheet in Models.xls to fit the same data. [b] Add the computation of standard deviation to the worksheet. [c] Compare the standard deviation σ for the quadratic model with that of the exponential model.

Answer: An exponential model is a better fit to this data than a quadratic model, because the best-fit exponential model y=3.11(1.0289)xy=3.11\cdot{{(1.0289)}^{x}} has σ = 0.46 million, while the best-fit quadratic model y=0.0051(x6.536)2+3.555y=0.0051\cdot{{(x-6.536)}^{2}}+3.555 has σ = 0.85 million, which is almost twice as large.

Can you think of another reason that a quadratic model is not likely to be appropriate for this data? (Hints: Where is the vertex of the parabola? What does this imply about the quadratic model’s prediction for years before 1780, the first year given in this dataset?)

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